Is there a similar command like "lid" on Ubuntu?

Question

Is there a similar command like "lid" on Ubuntu?

On RHEL, there is a command lid, which lists group users, no matter primary group or secondary group.

[root@192 ~]# id user1
uid=1000(user1) gid=1000(user1) groups=1000(user1),1001(g1)
[root@192 ~]# id user2
uid=1001(user2) gid=1002(user2) groups=1002(user2),1001(g1)
[root@192 ~]# id user3
uid=1002(user3) gid=1001(g1) groups=1001(g1)
[root@192 ~]# lid -g g1
 user3(uid=1002)
 user1(uid=1000)
 user2(uid=1001)
[root@192 ~]#

But it doesn’t exist on Ubuntu. Is there a similar one?

Asked By: Fajela Tajkiya

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Source

Answer 1

It does exist in Ubuntu, but it’s provided under a different name:

sudo libuser-lid -g g1

It’s part of the libuser package, install that if necessary:

sudo apt install libuser

The reason it’s not named lid is that lid is provided in the id-utils package and has a different purpose.

Answered By: Stephen Kitt

Answer 2

The described functionality can be achieved using standard utilities:

for u in $(getent group | grep '^g1:' | cut -d: -f4 | tr , 'n'); do
    printf "%s(uid=%d)n" $u $(id -u "$u")
done

Update: the command:

getent passwd | grep -E '^([^:]+:){3}'$(getent group | grep '^g1:' | cut -d: -f3)':' | cut -d: -f1

will retrieve lines from /etc/passwd corresponding to users whose primary group is g1. This can be combined with the previous command:

for u in $({ getent passwd | grep -E '^([^:]+:){3}'$(getent group | 
        grep '^g1:' | cut -d: -f3)':' | cut -d: -f1; 
    getent group | grep '^g1:' | cut -d: -f4 | tr , 'n'; }); do
    printf "%s(uid=%d)n" $u $(id -u "$u")
done | sort | uniq

with the added sorting and removal of duplicates at the end.

This command can be made into a shell function for convenience, using the group name as a parameter:

lid_replacement()
{
    for u in $({ getent passwd | grep -E '^([^:]+:){3}'$(getent group | 
            grep '^'$1':' | cut -d: -f3)':' | cut -d: -f1; 
        getent group | grep '^'$1':' | cut -d: -f4 | tr , 'n'; }); do
        printf "%s(uid=%d)n" $u $(id -u "$u")
    done | sort | uniq
}

# call as: `lid_replacement g1`

Edit: Updated regex to match the exact group name.

Edit 2: Updated to use getent(1) and added the function lid_replacement.

Answered By: Vilinkameni