Hide curl output
I’m making a curl request where it displays an html output in the console like this
<b>Warning</b>: Cannot modify header information - headers already sent by (output started at /home/domain/public_html/wp-content/themes/explicit/functions/ajax.php:87) in <b>/home/domain/public_html/wp-content/themes/explicit/functions/ajax.php</b> on line <b>149</b><br />......
etc
I need to hide these outputs when running the CURL requests, tried running the CURL like this
curl -s 'http://example.com'
But it still displays the output, how can I hide the output?
Thanks
From man curl
-s, –silent
Silent or quiet mode. Don’t show progress meter or error messages. Makes Curl mute. It will still output the data you ask for,
potentially even to the terminal/stdout
unless you redirect it.
So if you don’t want any output use:
curl -s 'http://example.com' > /dev/null
This one looks more elegant to me:
curl --silent --output /dev/null http://example.com
Also, if you want to see the HTTP code:
curl --write-out '%{http_code}' --silent --output /dev/null http://example.com
Full documentation is here.
One way to hide cURL output in the bash shell, is to redirect both stdout and stderr using the operator &> to /dev/null
curl http://example.com &> /dev/null